Question

A piece of wire is in the form of a rectangle with dimensions 26 cm and 18 cm.
it is reshaped and bent into the form of a circle. calculate the radius of the circle . (given pi = 22/7
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Answer 1

Answer:

radius is 14m.

Step-by-step explanation:

perimeter of rectangle = 2(l + b)

= 2(26 + 18)

= 88m

circumference of the circle = 88m

2πr = 88

r = 88 / ( 2 × 3.14 )

= 14.01 m or 14 m

Answer 2

The radius of circle is 14 cm.

Step-by-step explanation:

Consider the provided information.

A piece of wire is in the form of a rectangle with dimensions 26 cm and 18 cm.

The piece of wire is in the form of rectangle if we reshaped it that means the perimeter will remain same and the perimeter of rectangle becomes the circumference of circle.

The perimeter of the rectangle is: $P=2(l+b)$

Substitute l = 26 and b = 18 in above formula.

$P=2(26+18)$

$P=2(44)$

$P=88$

Hence, the perimeter is 88 cm that means the circumference of circle must be 88 cm.

Circumference of circle is: $C=2\pi r$

$88=2\times \frac{22}{7}\times r$

$r= \frac{88\times 7}{22\times 2}$

$r=2\times 7$

$r= 14$

Hence, the radius of circle is 14 cm.

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