A piece of wire is in the form of a square with side 33 mm. It is reshaped and bent into the form of a circle. What will be the radius of this circle?
Answers
Answer:
Area of sheet =πr
Area of sheet =πr 2
Area of sheet =πr 2 =
Area of sheet =πr 2 = 7
Area of sheet =πr 2 = 722
Area of sheet =πr 2 = 722
Area of sheet =πr 2 = 722 ×14×14
Area of sheet =πr 2 = 722 ×14×14=616cm
Area of sheet =πr 2 = 722 ×14×14=616cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2 Remaining Area =616−(77+3)
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2 Remaining Area =616−(77+3)=536cm
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2 Remaining Area =616−(77+3)=536cm 2
Area of sheet =πr 2 = 722 ×14×14=616cm 2 Area of 2 small circles =2×π×3.5×3.5=77cm 2 Area of rectangle =3×1=3cm 2 Remaining Area =616−(77+3)=536cm 2 .
Answer:- The radius of the circle = 21mm
Given in the question that:-
A piece of wire is in the form of a square whose sides are = 33mm
It is bent and formed into a circle.
We need to find the radius of the circle.
To find the radius of the circle first we need to find the perimeter of the given square and then the perimeter of the given square will be equal to the circumference of the circle. With the formula of the circumference of the circle we will be able to find the radius of the circle.
Solution:-
Sides of the square = 33mm
Perimeter of the square = 4×sides
= 4×33mm
= 132mm
Now,
The perimeter of the square is = the circumference of the circle = 132mm
Therefore,
The circumference of the circle = 2πr
132mm = 2×22/7×r
132×7/2×22 = r
3×7mm = r
21mm = r
Therefore, the radius of the circle is = 21mm
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