a piece of wire is in the form of rectangle whose length and breadth are 40 cm and 26 CM respectively if it is bent in the form of a circle find the diameter of the circle
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Answered by
8
hi Amman,
hint: perimeter of rectangle = perimeter of circle
2(l+b) = 2πr
2(40+26) = 2*22/7*r
132 = 22/7*2r
924 = 22 * d
d = 924 / 22
d = 42cm is the required diameter.
Hope it helped
Let me know if any doubts.
Cheers
hint: perimeter of rectangle = perimeter of circle
2(l+b) = 2πr
2(40+26) = 2*22/7*r
132 = 22/7*2r
924 = 22 * d
d = 924 / 22
d = 42cm is the required diameter.
Hope it helped
Let me know if any doubts.
Cheers
jish4you:
thank u for pointing out my mistake
i actually found area instead of perimeter :P
but now its all fine n correct
ok humun can only make mistake thanks
haha yea thnx
n welcome
let me know if any other doubts
will be happy to help :)
no next time clear my dought
sure anytime
Answered by
3
Here,
perimeter of reactange = perimeter of circle
2(l+b) = 2πr
L+b= πr
40+26 = 22/7×r
66×7/22 = r
r = 21
Radius= 21cm
Diameter = 2×21
= 42cm
perimeter of reactange = perimeter of circle
2(l+b) = 2πr
L+b= πr
40+26 = 22/7×r
66×7/22 = r
r = 21
Radius= 21cm
Diameter = 2×21
= 42cm
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