Question

A piece of wire is in the shape of an equilateral triangle whose sides measure 4.4 cm each. This wire is regent to form a circular ring. What is the area of the rings ​

Answer 1

Step-by-step explanation:

side of the equilateral triangle = 4.4 cm

perimeter of equilateral triangle

= 4.4 × 3

= 13.2 cm

this will be the circumference of circle = 2πr = 13.2 cm

2 × 22/7 × r = 13.2

$r = \frac{13.2 \times 7}{22 \times 2} \\ r = \frac{1.2 \times 7}{2 \times 2} \\ r = \frac{0.6 \times 7}{2} \\ r = 0.3 \times 7 \\ r = 2.1cm$

therefore the radius of circle is 2.1 cm

area of circle = πr²

$= \frac{22}{7} \times 2.1 \times 2.1 \\ = 22 \times 0.3 \times 2.1 \\ = 13.86 {cm}^{2}$

area of circle is 13.86 cm²

Hope you get your answer