A piece of wire is read drawn by pulling it until its length is doubled compare the new resistance with the original
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As per the formula,
R=PL/A
R-resistance
P-resistivity
L - length
A- area
Ashford the question the new length is double its original length
Hence the area becomes half its original area
hence the new formula for resistance will be
R'=p2L/A/2
R'=4pL/A
R'=4R
I hope this helps
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