a piece of wire of length 108cm is bent to form a semi circular arc bounded by its diameter. find radius
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12
Given,
Length of a wire is turned to Circumference of semicircle
πr + 2r= 108
r ( 22/7 + 2 ) = 108
r = 108 *7 / 36
r = 21 cm..
Therefore ,Radius = 21 cm.
Length of a wire is turned to Circumference of semicircle
πr + 2r= 108
r ( 22/7 + 2 ) = 108
r = 108 *7 / 36
r = 21 cm..
Therefore ,Radius = 21 cm.
subham1231:
in question it is semi circular arc bounded by its diameter
Answered by
2
radius= 21 cm
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