a piece of wire of length 48.8cm is bent in the form of an octagon . find the side of the octagon .
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Answer:
Area of the square=484cm
2
∴ Side of the square =
484
=22cm
⇒ Perimeter of the square =4×22=88cm
∵ (Circumference of the circle) = (perimeter of the square)
⇒2πr=88
⇒2×
7
22
×r=88
∴r=
2×22
88×7
=14cm
2
=
7
22
×14×14cm
2
=616cm
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