Question

a piece of wire of length 52 m is cut into two parts. each part is then bent to form a square. it is found that the combined area of the two squares is 109m sqaure. find the measures of the sides of the two square

Answer 1

Answer:

yes it simple we solve them

Answer 2

Answer:

10 m and 3 m

Step-by-step explanation:

If we make a square with the total length of the wire of length 52 m,

the perimeter, 4X = 52 m ,

so one side, X = 52/4 = 13 m

When we make two squares of sides y and z, the sum of perimeter will be 52 m.

ie, 4y + 4z = 52

4(y+z) = 52

y+z = 52/4 =13

Sum of their area = y² + z² = 109

So the sides of the two squares are such that their sum is 13 and sum og their squares is 109.

When we do trial and error we can find that 10 + 3 = 13

and 10² + 3² = 100 + 9  = 109