Question

A piece of wire of resistance
20 ahm so drown so that its lenght is increased to twice its original length. How will its (1) Resistance change (ii) resistivity change​

Answer 1

Answer:

A piece of wire of resistance

20 ahm so drown so that its lenght is increased to twice its original length. How will its (1) Resistance change (ii) resistivity change

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Answer 2

Answer:

A piece of wire of resistance 20 Omega is drawn so that its length is increased to twice is original length. ... When the length becomes 2l and cross-sectional area is A/2. Rnew=ρ(2l)A/2=4(ρl/A)=4(20Ω)=80Ω.

Explanation:

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