a piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length .calculate the resistance of wire in new situation.
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Explanation:
R=l/a
R2=l2/A2
ATQ,
20=l/a. (1)
R2= 2l/a/2
R2= 4(l/a)
R2=. 4×20. (from eq.1)
R2=80ohm. Ans
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