A piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice
Calculate the resistance of the wire in the new situation
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Answered by
6
Explanation:
resistance =20 ohm
resistance = pl/a
now length twice
corresponding area gets half
so resistance = p(2L)/(1/2)a
r=4(pl/a)
r=4×20
r=80ohm
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1
Explanation:
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