Question

 A piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length what will be the resistance of the wire in the new situation​

Answer 1

Answer:

when length of wire is doubled i.e 21 (say)

also its area of cross section becomes half i.e A\2

Resistance R = P|\A = 20

R' = p|/A

= p(21)*2/A

=4pl/A= 4(pl/A)

=4*20

=80 ohm

Explanation:

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