A piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length . Calculate the resistance of Wire in the new situation.
Answers
Answered by
1
Answer: 80 Ohm
Explanation:
Given resistance = R1 = 20 ohm
Let length of the wire = L
Therefore, new length of the wire = 2L
Since, when the length is doubled, cross sectional area of the wire becomes half.
Therefore, new resistance = R = 2L/ (A/2) =4L/A
R = 4 x 20 (since, L/A = resistance)
R = 80 ohm.
Similar questions