a piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length calculate the resistance. Nd plese solve it step by step
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Answered by
4
New R = n^2 R
= (2)^2× 20
4×20
=80 ohm
= (2)^2× 20
4×20
=80 ohm
Priyanshusrivastava:
also not satisfied with ur processss ... nd ans doesn't matching
80ohm
hmm
No i want detail ur tricks how could i understand
okk
Answered by
7
☆Hey Priyanshu☆
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Your answer is in the above pic:-----
Hope it will help you friend!
Thanks!
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================
Your answer is in the above pic:-----
Hope it will help you friend!
Thanks!
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vishesh come in inbox.. plz
Okkk
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