A piece of wire of resistance 20ohm is drawn out so that its length is increased to twice its original length calculate the resistance of a wire in new situation
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R = ρ L/A
= ρ L^2 / V
When wire is stretched volume (V) will remain constant.
∴ R ∝ L^2
If Length is increased to twice its length then resistance will increase by 4 times.
Hence,
Resistance of wire after stretched = 4 × Resistance of wire before stretched.
= ρ L^2 / V
When wire is stretched volume (V) will remain constant.
∴ R ∝ L^2
If Length is increased to twice its length then resistance will increase by 4 times.
Hence,
Resistance of wire after stretched = 4 × Resistance of wire before stretched.
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