Math, asked by shravangupta233, 1 year ago

A piece of wire of resistance 20resistance is drown
out so that its length is increased to twice its original length. Callulate the
resistance of the wire in the new
situation

Answers

Answered by risingphoenix24

0

Answer:

80

Step-by-step explanation:

the new resistance will be

2L/0.5A =4 times new resistance

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