A piece of wire of resistance 4 ohms is streched such that it's area of cross section becomes one forth of its original,then the resistance is
A 8 ohms
B 64 ohms
C 2 ohms
D 16 ohms
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Answer :- Finally resistance became 16timed equal to 64 ohm .
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d.16 is the ans
resitivity constant
length
A2=A1/4
R1/R2=pl/a/pl/a/4
4 goes up and pl and a gets cancelled as they are same
4/R2 =1/4
16ohms=R2
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