Question

A piece of wire of resistance 50Ω is drawn out so that its current is 5A.then find potential.​

Answer 1

Answer:

by ohms law

V=IR

= 50×5

=250 v

Answer 2

Answer :-

$\implies \boxed{ \sf{V = 250 \: volt \: }} \:$

To Find :-

→ Potential

Explanation :-

Given that :-

• Resistance (R) = 50Ω

• Potential (V) = ?
• Current (i) = 5 Ampere

We know that

$\implies \sf{ i = \frac{V}{R} }\: \\ \\ \implies \sf{ V = iR \: } \\ \\ \implies \sf{ V = 50 \times 5} \\ \\ \implies \boxed{ \sf{V = 250 \: volt \: }}$

Hence potential is 250 Volt .

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Some other formula

$(1) \sf{power (p)= v \: i \: } \\ \\ (2) \sf{power (p)\: = \frac{ {v}^{2} }{R} } \\ \\ (3) \sf{kinetic \: energy = \frac{1}{2} m {v}^{2} } \\ \\ (4) \sf{work = force \times dispacement} \\ \\ (5) \sf{potential \: energy = mgh \: }$