A piece of wire of resistance R is cut in to five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R| , then the ratio R/R| is_
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When we cut the wire into 5 parts, each one has a length of l5 and all other parameters remain unchanged. So the resistance of each new segment isR5. Connecting them parallel gives a network as shown in fig1. So the ratio RR′=25 , which is the required answer.
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