Question

A PIECE OF WIRE OF RESISTANCE R IS CUT INTO FIVE EQUAL PARTS.. THESE PARTS ARE THEN CONNECTED IN PARALLEL.. IF THE EQUIVALENT RESISTANCE OF THIS COMBINATION IS R', THEN THE RATIO R/R' IS................... ​

Answer 1

Answer:

hii mate....

resistant of each part will be 5/5

equivalent resistant will be

1/R =5/R +5/R +5/R +5/R +5/ R

so, R=R/25

If a resistance cut into n equal part then resistance of one resistor is = R/n

hence ,

resistance of all 5 resistor = R/5

all connected in parallel hence equivalent resistance 1/R1 = 1/R/5 + `1/R/5 + 1/R/5 + 1/R/5 + 1/R/5

1/R1 = 25/R

R/R1 =25

hope it helps you....

Answer 2

Let the length of resistance R be L

Let the resistance of each part after cutting be R

s

Since resistance is proportional to the length of the resistor,

R

s

=R/5.....................(i)

For resistors in parallel

1/R1+1/R2

By solving we get

R/R'= 25