A piece of wire of resistance R is cut into five equal parts these parts are then connected in parallel. The net resistance now will be
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Answer:
I think the answer is 0 net resistance
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Let the length of resistance R be L
Let the resistance of each part after cutting be R
s
Since resistance is proportional to the length of the resistor,
R
s
=R/5.....................(i)
For resistors in parallel,
R
′
1
=
R
1
1
+
R
2
1
+
R
3
1
+
R
4
1
+
R
5
1
⟹R
′
=R
s
/5................(ii)
From (i) and (ii),
R
′
=R/25
R/R
′
=25
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