Physics, asked by Aadrajput, 3 months ago

A piece of wire of resistance R is cut into five equal parts . These parts are then connected in parallel. If the equivalent resistance of this combination is R' the ratio R/R' is​

Answers

Answered by sharanyakhr5
75

Answer:

The ratio of R/R' is 25.

Attachments:
Answered by TheBrainliestUser
177

Answer:

  • The ratio R/R' is 25 : 1.

Explanation:

Given that:

  • A piece of wire of resistance R is cut into five equal parts.
  • These parts are then connected in parallel.
  • The equivalent resistance of this combination is R'.

To Find:

  • The ratio R/R'.

We know that:

In parallel combination.

  • R' = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + ...

Where,

  • R' = Equivalent resistance
  • 1/R₁, 1/R₂, 1/R₃, 1/R₄ are the resistance at different position.

Finding the equivalent resistance if R is cut into five equal parts:

⇢ 1/R' = 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5)

⇢ 1/R' = 5/(R/5)

⇢ 1/R' = (5 × 5)/R

⇢ 1/R' = 25/R

⇢ R' = R/25

⇢ R = 25R'

Finding the R/R':

  • R : R'
  • 25R' : R'

Cancelling R'.

  • 25 : 1

Hence,

  • The ratio R/R' is 25 : 1.
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