A piece of wire of resistance R is cut into five equal parts . These parts are then connected in parallel. If the equivalent resistance of this combination is R' the ratio R/R' is
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75
Answer:
The ratio of R/R' is 25.
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Answered by
177
Answer:
- The ratio R/R' is 25 : 1.
Explanation:
Given that:
- A piece of wire of resistance R is cut into five equal parts.
- These parts are then connected in parallel.
- The equivalent resistance of this combination is R'.
To Find:
- The ratio R/R'.
We know that:
In parallel combination.
- R' = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + ...
Where,
- R' = Equivalent resistance
- 1/R₁, 1/R₂, 1/R₃, 1/R₄ are the resistance at different position.
Finding the equivalent resistance if R is cut into five equal parts:
⇢ 1/R' = 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5) + 1/(R/5)
⇢ 1/R' = 5/(R/5)
⇢ 1/R' = (5 × 5)/R
⇢ 1/R' = 25/R
⇢ R' = R/25
⇢ R = 25R'
Finding the R/R':
- R : R'
- 25R' : R'
Cancelling R'.
- 25 : 1
Hence,
- The ratio R/R' is 25 : 1.
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