A piece of wood floats, three quarters immersed in water. What is it's density?
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Explanation: in case of floatation, Fnet=0
Weight of body=upthrust
Mg=Weight of the fluid displaced by the body
(Vd) x g=V(of fluid displaced) x d(of fluid) x g
V x d = 3/4 x V x 10^3 (of water)
d = 3/4 x 1000
d = 750 kg/m^3
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