Question

a piece of wood of relative density 0.36 floats in oil of density 0.9 .fraction of volumw of wood above oil is?

Answer 1

wood is denser that that oil............

Answer 2

Answer:

Fraction of volume of wood above oil is 0.96.

Explanation:

Let, the volume of wood be v and  volume of wood in inside=′a′

Density of wood =ρ₁ =0.36 [Relative density = density]

Density of oil =ρ₂=0.9

From Buoyancy principle,

Buoyant force =aρ₂g (weight of liquid displace)

weight of wood =vρ₁g

in equilibrium

aρ₂g=vρ₁g

⇒ a=vρ₁÷ρ₂

⇒ a=(0.36÷0.9)v= 0.04v

∴  volume of wood outside oil

v′ =v−a = v− 0.04v

⇒ v′= 0.96v

 ⇒ v'÷v= 0.96

∴ Fraction of volume of wood above oil is 0.96.

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