A piece of wood weighs 10 g in air. When a heavy piece of metal is suspended below it, the metal being submerged in water. The ' weight of wood in air + metal in water is 14 g . The 'weight ' when both the wood and metal are submerged in water is 2g . Find the volume and density of wood .
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Answered by
6
Answer:
The metal plus wood has an apparent mass of 14g. with the metal submerged (wood clear of water).
When the wood is allowed to sink, it displaces (14 - 2) = 12g. of water.
The volume of 12g. of water is 12cc.
Volume of wood = 12cc., and density = (10g/12cc) = 0.83g/cc.
Answered by
6
Answer:
Mass of the wood object in air=10g
The apparent weight of metal and wood object combined is 14 g
When both wood and metal object are submerged in water,
The wood object displaces (14-2)g=12g of water
12g of water is equivalent to 12cc of water because water has a density of 1g/cc
So the volume of the wood object is 12cc
And density of the wood object=Mass/Volume=10g/12cc
Density of wood object=0.83g/cc
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