A piece of work by A in 25 days and B in 20 days. A and B works together for 5 days, after that A leaves. In how many days B will finish the remaining work?
Answers
Answer:
11 Day
Explanation :
Generally these Questions are little bit tricky but lets solve it
As we see in question it is given
A completed a piece of work in 25 day
In 1 day A can complete 1/25th part of piece of work
Similarly ,
B completed same piece of work in 20 day
and In 1 day B can complete 1/20th part of piece of work
And If they work Together ,
means ,
In one day (A + B) can complete
= (1/20th + 1/25th) part of piece of work
= (5+4)/100th part of piece of work
= 9/100th part of piece of work
i.e.,
In 1 day (A + B) can complete 9/100th part of piece of work
or for A and B (A + B) It took 100/9 day to do that piece of work
Since,
In 1 day (A + B) can complete 9/100th part of piece of work
In 5 day (A +B) can complete [5*(9/100)]th part of piece of work
= 45/100th part of piece of work
But still 55/100th part of work is left
and since A leave left work will be done by B only
and previously we get,
In 1 day B can complete 1/20th part of piece of work
or B take 1 day to complete to 1/20th part of piece of work
and to complete 55/100th part of work B will take days =
= (55/100) / (1/20)
= 55 * 20 / 100
=55/5
= 11 Days
I know Explanation is too long but for better explanation i did it
i Hope you get the answer Thanks !!!!!!