A piece of work by A in 25 days and B in 20 days. A and B works together for 5 days, after that A leaves. In how many days B will finish the remaining work?
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Answered by
1
Answer:
Correct option is
B
11 days
Step-by-step explanation:
A's 1 day's work =
25
1
Similarly, B's 1 day's work =
20
1
A's and B's together 1 day's work
25
1
+
20
1
=
100
4
+
100
5
=
100
4+5
=
100
9
Their 5 day's work together = 5 x 1 day's work
1−
100
45
=
100
100
−
100
45
=
100
100−45
=
100
55
Now, this remaining work is done by B.
Let B takes x days to complete it.
20
1
×x=
100
55
⇒x=
100
55
×20
⇒x=
5
55
⇒x=11
Hence, B will finish the remaining work in 11 days
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