Math, asked by devojusrinu00713, 7 months ago

A piece of work can be completed in 18 days by 10 mem and 6 boys.The men work 9 hours and boys 7.5 hours per day and 3 boys do as much work in an hour as two men do.How many hours would it take if the work is done by one man.​

Answers

Answered by kakotydaniel
0

Answer:To complete the work in 18 days 10 men work 6 hours  day

To complete the work in 18 days 1 man work (10 x 6) hours a day

To complete the work in  day 1 man will work (6 x 10 x 18) hours in a day (less days, less men, more hours)

To complete the work in 1 day 15 men will work  

15

(6×10×18)

​  

 hours a day

∴ To complete the work in 12 days 15 men will work  

12×15

6×10×18

​  

 hours a day  

(more days, more men, less hours) = 6 hours a day

Step-by-step explanation:

Answered by pinkypearl301
0

Step-by-step explanation:

To complete the work in 18 days 10 men work 6 hours day

To complete the work in 18 days 1 man work (10 x 6) hours a day

To complete the work in day 1 man will work (6 x 10 x 18) hours in a day (less days, less men, more hours)

To complete the work in 1 day 15 men will work

15

(6×10×18)

hours a da

∴ To complete the work in 12 days 15 men will work

12×15

6×10×18

hours a day

(more days, more men, less hours) = 6 hours a day

A piece of work can be completed in 18 days by 10 mem and 6 boys.The men work 9 hours and boys 7.5 hours per day and 3 boys do as much work in an hour as two men do.How many hours would it take if the work is done by one man.​

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