Math, asked by pushpamadhuri, 8 months ago

A piece of work can be completed in 18 days by 10
men and 6 boys. The men work 9 hours and boys 7,
hours per day and 3 boys do as much work in an
hour as two men do. How many hours would it take
if the work is done by one man.​

Answers

Answered by KingOfLions
0

Step-by-step explanation:

To complete the work in 18 days 10 men work 6 hours day

To complete the work in 18 days 1 man work (10 x 6) hours a day

To complete the work in day 1 man will work (6 x 10 x 18) hours in a day (less days, less men, more hours)

To complete the work in 1 day 15 men will work

15

(6×10×18)

hours a day

∴ To complete the work in 12 days 15 men will work

12×15

6×10×18

hours a day

(more days, more men, less hours) = 6 hours a day

Answered by skroja2019
0

A piece of work can be completed in 18 days by 10

men and 6 boys. The men work 9 hours and boys 7,

hours per day and 3 boys do as much work in an

hour as two men do. How many hours would it take

if the work is done by one man.​

1

SEE ANSWER

ADD ANSWER

To complete the work in 18 days 10 men work 6 hours day

To complete the work in 18 days 1 man work (10 x 6) hours a day

To complete the work in day 1 man will work (6 x 10 x 18) hours in a day (less days, less men, more hours)

To complete the work in 1 day 15 men will work

15

(6×10×18)

hours a day

∴ To complete the work in 12 days 15 men will work

12×15

6×10×18

hours a day

(more days, more men, less hours) = 6 hours a day

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