Question

A piece of work can be done by 16 men in 8 days 12 hour in a day .How many men are needed to complete another work which is three times the first one in 24 days woring 8 hour in a day

Answer 1

Hours taken to do work in case 1=12*8=96

16 men in 96 hrs=1 work

3(16*96)=3 work

No. Of men required to do 3 work = x

Hours required to do work in case 2 = 8*24= 192

X*192=3 work

3(16*96)=x*192

X=3*16*96/192

X=24

Answer 2

M1=16 , M2=?
D1=8 , D2=24
T1=12 , T2=8
M1 T1 D1 = M2 T2 D2
16×12×8=M2×8×24
1536=M2×192
M2=1536÷192
M2=8
8 men are needed to complete another work