Question

A Piece of work is to be completed in 18 months. If 315 men is finished it in 16 months, then how many men will required to complete the work in time.

Answer 1

we will use the formula (m1×d1)/(w1)= (m2×d2) /(w2)
and according to the question we have 
let
men m1= 315
months d1 = 16
w1 should be w1= piece of work 1

m2=x
d2=18
w1=1
(m1×d1)/(w1)= (m2×d2) /(w2)
(315*16)/(1)= (X*18)/(1)

5040=18X
X=5040/18
X=280
so 280 man required to complete same peace of work in 18 months 

Answer 2

I think 280 man required to do work in 18 days