A piece of work requires 8 men and 4 women to complete a work in 6 days. efficiency of a man is twice that of a woman. if 8 men and 4 women start working together, after 2 days, 4 men are replaced by 4 women. how many more days would be required to complete the work?
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According to the question,
1 man = 2 women
∴ 8 men + 4 women
= (16 + 4) women = 20 women
4 men + 8 women = 16 women
20 women's 2 days' work
= 26=13
Remaining work = 1 - 13 = 23
∵ 20 women complete 1 work in 6 days.
∴ 16 women will do 23 work in
= 20×616×23 = 5 days
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