A piece of zinc at a temperature of 20 degree celcius weighing 65.38 g is dropped into 180 g of boiling water. The specific heat capacity of zinc is 0.4 joule per gram per degree celcius and that of water is 4.2 joule per gram per degree celcius . what is the final common temperature reached by both the zinc and water?
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Answer:
hope I think it will help you
Explanation:
Zn
.S
Zn
.(T
f
−T
i
)+m
H
2
O
.S
H
2
O
.(T
f
−T
i
)=0
⟹(65.38gm)(0.4J/g
o
C)(T
f
−20
o
C)+180gm(4.20J/g
o
C)×(T
f
−100
o
C)=0
⟹[(65.38)(0.4)+180(420)]T
f
=(65.38)(0.4)(20)+(180)(4.20)(100)
T
f
=[
(65.38)(0.4)+(180)(4.20)
(65.38)(0.4)(20)+(180)(4.20)(100)
]=97.3
o
C
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