Question

A piece weighing 3 kg in air was found to weight 2.5 kg when submerged in water .Specfic gravity is

Answer 1

Specific gravity=(Weight of air/(weight of air - weight of water))

=3/(3-2.5)
=3/0.5
=6

HOPE IT HELPS!!!

Answer 2

Specific Gravity is 6

1. The formula for Specific Gravity is given by: density of object/density of water.                                                        
2. Weight in air/Weight in (air-water)
3. weight of object in air is 3 kg.
4. weight of object in water is 2.5 kg.
5. 3/(3-2.5)
6. 3/0.5
7. 6