a piece wire of resistance 20ohm is drawn out so thatits length is increased to twice its original length calculate the resistance of the wire is the new situation
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Resistance = resistivity x legnth / area
R = p l/A
40 = p l/A ---------(1)
V= Al = A'L
A'= Al / L
A' = Al /2l
A' = A /2
R'= p L/A'
R'= p 4l / A
R' = 4 p l/A
R' = 4 x 40 ( put value of pl/A
R' =160 ohm
R = p l/A
40 = p l/A ---------(1)
V= Al = A'L
A'= Al / L
A' = Al /2l
A' = A /2
R'= p L/A'
R'= p 4l / A
R' = 4 p l/A
R' = 4 x 40 ( put value of pl/A
R' =160 ohm
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