Question

A pig runs rightward 20m to eat a juicy apple it then walks leftward 5m to eat a nut finally it walks leftward another 25m to eat another nut the total time taken by the pig was 300 seconds what was the average velocity and average speed over this time

Answer 1

Given :-

• A pig runs rightward 20m to eat a juicy apple.
• Then walks leftward 5m to eat a nut.
• Finally it walks leftward another 25m to eat another nut.
• The total time taken by the pig was 300 seconds.

To Find :-

• what was the average velocity and average speed over this time ?

Solution :-

→ Total displacement = 20 m rightward - 5 m leftward - 25m leftward = (+20m - 5m - 25m) = (-10) m .

→ Total time taken = 300 seconds.

So,

→ Average velocity = (Total displacement) / (Total Time taken) = (-10)/300 = (-1/30) = -(0.033) m/s . { Negative sign shows that, direction is in backward.}

Now,

→ Total distance covered by pig = 20m + 5 m + 25m = 50m..

→ Total time taken = 300 seconds.

So,

→ Average Speed = (Total distance) / (Total Time taken) = (50/300) = (1/6) = (0.166) m/s. (Ans.)

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