Question

A pigeon ate in total 1122 earth worms on 4 consecutive nights each night he ate 25 more than on the night before how many earth worms dod pigeon eat on the first night

Answer 1

Answer:

243 earthworm pigeon eat on the first night.

Step-by-step explanation:

Given:

Total Earthworm that pigeon ate = 1122 in 4 nights

Each he eat 25 more earth worm than previous night.

To find: Number of earthworm he eat on first night.

Clearly Number of earthworm on a night are forming an AP with number of terms, n = 4 and common difference, d = 25 and Sum of 4 terms, $S_n$ = 1122

Using formula of sum of n term, $S_n=\frac{n}{2}(2a+(n-1)d)$

let a be the first term of AP and the number of earthworm he eat on first night.

According tot he Question,

$S_4=\frac{4}{2}(2a+(4-1)25)$

$1122=2(2a+3(25))$

$561=2a+75$

2a = 561 - 75

2a = 486

a = 243

Therefore, 243 earthworm pigeon eat on the first night.

Answer 2

Step-by-step explanation:

night.

Step-by-step explanation:

Given:

Total Earthworm that pigeon ate = 1122 in 4 nights

Each he eat 25 more earth worm than previous night.

To find: Number of earthworm he eat on first night.

Clearly Number of earthworm on a night are forming an AP with number of terms, n = 4 and common difference, d = 25 and Sum of 4 terms, S_nS

n

= 1122

Using formula of sum of n term, S_n=\frac{n}{2}(2a+(n-1)d)S

n

=

2

n

(2a+(n−1)d)

let a be the first term of AP and the number of earthworm he eat on first night.

According tot he Question,

S_4=\frac{4}{2}(2a+(4-1)25)S

4

=

2

4

(2a+(4−1)25)

1122=2(2a+3(25))1122=2(2a+3(25))

561=2a+75561=2a+75

2a = 561 - 75

2a = 486

a = 243

Therefore, 243 earthworm pigeon eat on the first night.