Question

A pigeon flies at 36 km/h to and fro between two cars moving toward each other on a straight road, starting from the first car when the the car separation is 40 km. The first car has a speed of 16 km/h and the second one has a speed of 25 km/h.By the time the cars meet head on,what are the (A) total distance and (B) net displacement flown by the pigeon?

Answer 1

Hello Dear.

Here is the answer---

Given ⇒

Total Distance between the Car = 40 km.
Relative Speed of the Car = Speed of the First Car + Speed of the Second Car
= 16 + 25
= 41 km/hr.

Now, Using the Formula,

Time = Total Distance/Relative Speed
∴ Time = 40/41 hrs.

(A) ⇒ 
Now, In this time period, distance travels by the bird = Speed of the bird × 40/41

= 36 × 40/41
= 35.12 km.

Thus, Total Distance covered by the Bird is 35.12 km.

(B) ⇒
Also, In this time period Distance travels by the First Car = Speed of the First Car × 40/41
= 16 × 40/41
= 15.61 km.

At this distance, both the car meets.
∴ Net Displacement = 15.61 km.
[∵ Displacement covered by the Car = Distance from the starting point to the meeting point.]



Hope it helps.