A piggy bank contains $2.65 in nickels and dimes. If the number of nickels is 7 less than three times the number of dimes, how many of each kind of coin are there?
Answers
Answer:
Step-by-step explanation:
total amount in piggy bank = $2.65
let the number of dimes be x,so
the number of nickels will be 3x-7
value of one nickel = $0.05
the value of 3x-7 nickels will be = 0.05(3x-7)
=5/100*(3x-7)
=15x-35/100
value of one dime =$0.10
the value of x no of dimes = 0.10*x
=1x/10
therefore,ATQ
15x-35/100 + 1x/10 = 2.65
15x-35/100 + 10x/100 = 2.65
25x-35/100 = 2.65
25x-35 = 2.65*100
25x-35 = 265
25x = 265 + 35
25x = 300
x = 300/25
x = 12
thus, there are x = 12 dimes and 3x-7 = (3*12)-7 = 29 nickels in the piggy bank
Answer:
12 dimes and 29 nickels
Step-by-step explanation:
the value of 3x-7 nickels will be = 0.05(3x-7)
=5/100*(3x-7)
=15x-35/100
value of one dime =$0.10
the value of x no of dimes = 0.10*x
=1x/10
15x-35/100 + 1x/10 = 2.65
15x-35/100 + 10x/100 = 2.65
25x-35/100 = 2.65
25x-35 = 2.65*100
25x-35 = 265
25x = 265 + 35
25x = 300
x = 300/25
x = 12
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