Question

a piggy bank contains 50 P coins, Fifty, rupees 1 coins, twenty rupees 2 coin, and 10 rupees 5coins if it is equally likely that one of the coin will fall out when the bank is turned upside down.What is the Probability that the coin a) will be a 50P coin B) will be more than the value of rupees 1coin C) will boe less than the value of rupees 5 coin D) will be a rupees 1coin or 2coin?​

Answer 1

Answer:

(i) Total number of coins = 100 + 50 + 20 + 10

= 180

Total number of possible outcomes of a coin will fall out = 180

Number of 50 p coins = 100

Number of favourable outcomes relating to fall out of a 50 p coin = 100

Now, P(of getting a 50 p coin)

Number of favourable outcomes ÷ Total number of possible outcomes

\bf\huge\frac{100}{180}

180

100

= \bf\huge\frac{5}{9}

9

5

(ii) P(not a 5 coin) = 1 – P(5 coin)

= \bf\huge 1-\frac{10}{180}1−

180

10

= \bf\huge\frac{17}{18}

18

17

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