Question

A piggy bank contains ecatly 6 dimes and 10 nickels .if four are selected at random from the bank, without replacemnt , and athe first 3 selected are nickels , what is the probability that fourth coin selected is also a nickel ?

Answer 1

Answer:

7/13

Step-by-step explanation:

Total,= 16

Nickel=10

Dimes = 6

3 nickel are taken out

Now total= 13

No. Of nickel remaining = 10-3=7

So no.of outcomes / total no. Of outcomes

So the answer will be 7/13

Answer 2

The probability that fourth coin selected is also a nickel is $\dfrac{7}{13}$ .

Explanation:

Given : A piggy bank contains exactly 6 dimes and 10 nickels .

Total coins = 6+10=16

Four are selected at random from the bank, without replacement ,.

If the first three are nickels , then the total coins left  in piggy bank= 16-3=13 (Total outcomes)

The number of nickels left =10-3=7   (Favorable outcomes)

Then, the  probability that fourth coin selected is also a nickel will be $\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}\\\\=\dfrac{7}{13}$

Hence, The probability that fourth coin selected is also a nickel is $\dfrac{7}{13}$ .

# Learn more :

If the probability of a win is 0.12 and the probability of a draw is 0.6, what is the probability of a loss?

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