Math, asked by devika3110, 2 months ago

a piggy bank contains hundred 50 paise coins, fifty 1 rupees coin twenty 2rupees coin and ten 5 rupees coins if it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be of value more than rupees 1​

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Answered by gouravkuamrverma2
0

Answer:

a piggy bank contains hundred 50 paise coins, fifty 1 rupees coin twenty 2rupees coin and ten 5 rupees coins if it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be of value more than rupees 1

Answered by ishitachanda93
1

Answer:

The total number of coins in the piggy bank = number of coins of 50 paise + number of coins of 1 rupee + number of coins of 2 rupees + number of coins are 5 rupees = 100 + 50 +20 +10 = 180 coins. Total number of coins = 180. Hence, the probability that a 50 paise win is 59.

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