Question

A piggy bank contains hundred 50p coins, fifty ₹1 coins, twenty ₹2 coins and ten ₹5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin
(i) will be a 50 p coin?
(ii) will not be a ₹5 coin?
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Answer 1

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Total no. of coins = 100 + 50 + 20 + 10 = 180

Total no. of coins = 100 + 50 + 20 + 10 = 180P(E)

= (Number of favourable outcomes/ Total number of outcomes)

(i) Total number of 50 p coin = 100

P (50 p coin) = 100/180 = 5/9 = 0.55

(ii) Total number of ₹5 coin = 10

P (₹5 coin) = 10/180 = 1/18 = 0.055

∴ P (not ₹5 coin)

= 1 – P (₹5 coin)

= 1 – 0.055

= 0.945

Answer 2

Answer:

Total number of coins = 100 + 50 +20+10 = 180

So the total number of possible outcomes = 180

(i)Let A be the event that the coin is 50 p

So the total number of possible outcomes for the event A is 100

So the required probability is = 100 /180 = 5/9

(ii)Let B be the event that the coin is ₹5

So the total number of possible outcomes for the event B is 10

So the probability is the coin is ₹5 = 100 /180 = 10/18

So the probability is the coin is ₹5 = 1-10/18 = 8/18 = 4/9

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