A piggy bank contains hundred 50p coins, fifty I coins, twenty 2 coins and tens
coins. If it is equally likely that one of the coins will fall out when the bank is turned
upside down, what is the probability that the coin (1) will be a 50 p coin ? (ii) will not be
a 5 coin?
Answers
Answered by
6
Step-by-step explanation:
Total number of coins in the piggy bank =100+50+20+10=180.
i)
P(50p coin) =
total number of coins
number of 50p coins
=
180
100
P(50p coin) =
9
5
ii)
Number of c 5 coins =10
Number of coins which are not c 5=170
P(coin not being c 5) =
180
170
=
18
17
Answered by
6
Answer:
Total number of coins in the piggy bank =100+50+20+10=180.
i)
P(50p coin) = number of 50p coins/total number of coins
=100/180
P(50p coin) = 5/9
ii)
Number of c 5 coins =10
Number of coins which are not c 5=170
P(coin not being c 5) = 170/180
=17/18
Similar questions