Math, asked by twinklevasudev, 9 months ago

A piggy bank contains hundred 50p coins, seventy 1 coin, fifty 2 coins and thirty 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50-p or a 1 coin? (ii) will not be a 5 coin (iii) will be 50p or a 2rs coin

Answers

Answered by mahikaagarwal
0

Answer: this is so easy. this is ch 15 of ncert na? probability right?

Step-by-step explanation:

Answered by aravindkumar4456
2

Total no. of coins = 100 + 50 + 20 + 10 = 180

Total no. of coins = 100 + 50 + 20 + 10 = 180P(E)

= (Number of favourable outcomes/ Total number of outcomes)

(i) Total number of 50 p coin = 100

P (50 p coin) = 100/180 = 5/9 = 0.55

(ii) Total number of ₹5 coin = 10

P (₹5 coin) = 10/180 = 1/18 = 0.055

∴ P (not ₹5 coin)

= 1 – P (₹5 coin)

= 1 – 0.055

= 0.945

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