Question

A piggy bank contains hundred 50p coins, seventy rs 1 coins, fifty rs 2 coins and thirty rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin cbse2013-4m (a) will be a rs. 1 coin? (b) will not be a rs. 5 coin? (c) will be a rs. 50 p or rs.2 coin?

Answer 1

$\mathfrak{Question:-}$

A piggy bank contains hundred 50p coins, seventy rs 1 coins, fifty rs 2 coins and thirty rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin cbse 2013- 14 m (a) will be a rs. 1 coin? (b) will not be a rs. 5 coin? (c) will be a rs. 50 p or rs.2 coin?

$\mathfrak{Question:-}$

$\mathbf{Given:-}$

No. of 50p coins = 100

No. of ₹ 1 coins = 70

No. of ₹ 2 coins = 50

No. of ₹ 5 coins = 30

So, total No. of coins = 100 + 70 + 50 + 30 = 250

1). Probability of ₹ 1 coin

Favourable no. of elementary events = 70

$\bold{Probability = \frac{Favourable\; Outcome}{Total\; Outcome}}$

$\bold{Probability = \frac{70}{250}}$

$\bold{\boxed{\boxed{\bold{Probability = \frac{7}{25}}}}}$

2). Probability of ₹ 5 coin

Favourable no. of elementary events = 30

$\bold{Probability = \frac{Favourable\; Outcome}{Total\; Outcome}}$

$\bold{Probability = \frac{30}{250}}$

$\bold{\boxed{\boxed{\bold{Probability = \frac{3}{25}}}}}$

3). Probability of 50p coin

Favourable no. of elementary events = 100

$\bold{Probability = \frac{Favourable\; Outcome}{Total\; Outcome}}$

$\bold{Probability = \frac{100}{250}}$

$\bold{\boxed{\boxed{\bold{Probability = \frac{10}{25}}}}}$

4). Probability of ₹ 2 coin

Favourable no. of elementary events = 50

$\bold{Probability = \frac{Favourable\; Outcome}{Total\; Outcome}}$

$\bold{Probability = \frac{50}{250}}$

$\bold{\boxed{\boxed{\bold{Probability = \frac{5}{25}}}}}$

Answer 2

Answer:

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