a piggy bank contains rupees 460 in coins of denominations rupees 2 ,5 and rupees 10 . the number of rupees 5 coins is two times the number of Rs 2 coins if the total number of coins is 100 , find the number of coins of each denomination in the Piggy Bank
Answers
Let the number of Rs 2 coins = x
Therefore, the numbers of Rs 5 coins = 2x
Since, the total number of coins are 100.
Therefore, the number of Rs 10 coins = 100-(x+2x)
= 100-3x
Total amount = Rs 460
2(x) + 5(2x) + 10(100-3x) = 460
2x + 10x + 1000 - 30x = 460
12x - 30x + 1000 = 460
-18x = 460 - 1000
-18x = -540
x = 30
Therefore, the number of coins of Rs 2 = x = 30
The number of coins of Rs 5 = 2x = 60
The number of coins of Rs 10 = 100 - 3x
=
= 10.
Therefore, there are 30 coins of Rs 2, 60 coins of Rs 5 and 10 coins of Rs 10.
Answer: Let the number of Rs 2 coins = x
Therefore, the numbers of Rs 5 coins = 2x
Since, the total number of coins are 100.
Therefore, the number of Rs 10 coins = 100-(x+2x)
= 100-3x
Total amount = Rs 460
2(x) + 5(2x) + 10(100-3x) = 460
2x + 10x + 1000 - 30x = 460
12x - 30x + 1000 = 460
-18x = 460 - 1000
-18x = -540
x = 30
Therefore, the number of coins of Rs 2 = x = 30
The number of coins of Rs 5 = 2x = 60
The number of coins of Rs 10 = 100 - 3x
=
= 10.
Therefore, there are 30 coins of Rs 2, 60 coins of Rs 5 and 10 coins of Rs 10.
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