Question

a piggy bank has only one rupee and 50 paise coins. If there are three times as
many 50.paise coins as one rupee coins and the total money in this bank is 35.
How many coins of each kind are there?​

Answer 1

Answer:

one rupee coins=14

50 paise coins=42

Step-by-step explanation:

let one rupee coins=x

then 50 paise coins=3x

total money= x+3x/2=35

2x+3x=70

5x=70

x=14

so

one rupee coins=14

50 paise coins=42

Answer 2

$\bf{\large{\underline{\underline{Answer:-}}}}$

Numbers of 1 Rupee coins = 14

Number of 50 paise coins = 42

$\bf{\large{\underline{\underline{Explanation:-}}}}$

Given :-

A piggy bank has 1 Rupee and 50 paise coins

If there are three times as

many 50.paise coins as one rupee coins

Total money in piggy bank is Rs. 35

To find :- Number of coins in each denomination

Solution :-

Let the number of 1 Rupee coins in piggy bank be x

50 paise coins in piggy bank = 3 times as many as 1 Rupee coins = 3(x) = 3x

First we need to find how much money in the form of 50 paise and 1 Rupee.

Money in the form of 1 Rupee coins = 1(3x) = Rs. x

Now we need to money in the form of 50 paise coins.

We know that 50 Paise = Rupee/2 i.e, 1/2

So, Money in the form of 50 paise coins = 1/2 (3x) = Rs. 3x/2

Total money = Rs. 35

Total money = Money in the form of 1 Rupee coins + Money in the form of 50 paise coins

According to the question :-

Equation formed :-

$\boxed{\tt{ \star \: \: x + \dfrac{3x}{2} = 35}}$

$\tt{\implies{ \dfrac{x(2)}{1(2)} + \dfrac{3x}{2} = 35}}$

$\tt{\implies{ \dfrac{2x}{2} + \dfrac{3x}{2} = 35}}$

$\tt{\implies{\dfrac{2x + 3x}{2} = 35}}$

$\tt{\implies{\dfrac{5x}{2} = 35}}$

$\tt{\implies{5x = 35 \times 2}}$

$\tt{\implies{5x = 70}}$

$\tt{\implies{x = \dfrac{70}{5}}}$

$\tt{\implies{x = 14}}$

Therefore Number of 1 Rupee coins = x = 14

Therefore Number of 50 paise coins = x = 10Number of 1 rupee coins = 3x = 3(14) = 42

$\bf{\large{\underline{\underline{Verification:-}}}}$

To check whether the answer is correct or not substitute number of coins of each denomination in the equation that is formed to solve.

$\tt{\implies{14 + \dfrac{42}{2} = 35}}$

$\tt{\implies{14 + 21= 35}}$

$\tt{\implies{35 = 35}}$