A pilpt of helicopter ,at an altitude of 1200m finds that two ships are sailing towards ot in the same direction.The angles of depression of the ships are observed from the helicopter are 60° and 45° respectively.Fimd the distance between the two ships
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Answer:
508 metres
Step-by-step explanation:
let AB be the height at which the pilot is flying
AB=1200 m
From the information, we construct a diagram as given
here,
x=distance between ships
Now,in triangle ABC
tan60°=AB÷BC
root (3)=1200÷y
y=1200÷root (3)
y=400×root (3)---------------A
In triangle ABD
tan45°=AB÷BD
1=1200÷x+y
x+y=1200
x=1200-y
(we have y=400×root (3))
x=1200-400×root (3)
(we know that root (3)=1.73)
x=1200-400×1.73
x=1200-692
x=508 metres
Therefore, the distance between ships is 508 metres
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