Question

A PIPE CAN FILL A CISTERN IN 12min AND ANOTHER PIPE CAN FILL IT IN 15min, BUT A THIRD PIPE CAN EMPTY IT IN 6min. THE FIRST TWO PIPES ARE KEPT OPEN FOR 5min IN THE BEGINNING AND THEN THE THIRD PIPE IS ALSO OPENED. TIME TAKEN TO EMPTY THE CISTERN IS???

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Answer 1

⭐$\huge\underline\mathfrak\red{Answer}$⭐

Let the number of minutes taken to empty the cistern be x min.

According to the question,

x x+5 x+5 = 0

6 12 15

x - x - 5 - x - 5 = 0

6 12 12 15 15

x - x - x = 5 + 5

6 12 15 12 15

10x - 5x - 4x = 25+20

60 , 60

x = 45

60 60

x=45 min

⭐$\huge\underline\mathfrak\red{</em><em>F</em><em>o</em><em>l</em><em>l</em><em>o</em><em>w</em><em>m</em><em>e</em><em>}$⭐

Verify this answer

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

$\huge{\underline{\underline{\mathfrak{let}}}}$

The number of minutes taken to empty the cistern be X min.

$\huge{\underline{\underline{\mathfrak{atq}}}}$

» x x+5 x+5 = 0

» 6 12 15

» x - x - 5 - x - 5 = 0

» 6 12 12 15 15

» x - x - x = 5 + 5

» 6 12 15 12 15

» 10x - 5x - 4x = 25+20

» 60 , 60

» x = 45

» 60 60

» x=45 min

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$